This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
ace16 = a c e = a(=1010) c(=1100) e(=1110) = 1010110011102
the Final answer: ace16 = 1010110011102
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
10∙162+12∙161+14∙160 = 10∙256+12∙16+14∙1 = 2560+192+14 = 276610
got It: ace16 =276610
Translate the number 276610 в binary like this:
the Integer part of the number is divided by the base of the new number system:
2766 | 2 | | | | | | | | | | | |
-2766 | 1383 | 2 | | | | | | | | | | |
0 | -1382 | 691 | 2 | | | | | | | | | |
| 1 | -690 | 345 | 2 | | | | | | | | |
| | 1 | -344 | 172 | 2 | | | | | | | |
| | | 1 | -172 | 86 | 2 | | | | | | |
| | | | 0 | -86 | 43 | 2 | | | | | |
| | | | | 0 | -42 | 21 | 2 | | | | |
| | | | | | 1 | -20 | 10 | 2 | | | |
| | | | | | | 1 | -10 | 5 | 2 | | |
| | | | | | | | 0 | -4 | 2 | 2 | |
| | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | 0 | | |
|
the result of the conversion was:
276610 = 1010110011102
the Final answer: ace16 = 1010110011102