This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from binary to hexadecimal like this:
01111110000011002 = 0111 1110 0000 1100 = 0111(=7) 1110(=E) 0000(=0) 1100(=C) = 7E0C16
the Final answer: 01111110000011002 = 7E0C16
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙215+1∙214+1∙213+1∙212+1∙211+1∙210+1∙29+0∙28+0∙27+0∙26+0∙25+0∙24+1∙23+1∙22+0∙21+0∙20 = 0∙32768+1∙16384+1∙8192+1∙4096+1∙2048+1∙1024+1∙512+0∙256+0∙128+0∙64+0∙32+0∙16+1∙8+1∙4+0∙2+0∙1 = 0+16384+8192+4096+2048+1024+512+0+0+0+0+0+8+4+0+0 = 3226810
got It: 01111110000011002 =3226810
Translate the number 3226810 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
32268 | 16 | | | |
-32256 | 2016 | 16 | | |
C | -2016 | 126 | 16 | |
| 0 | -112 | 7 | |
| | E | | |
|
the result of the conversion was:
3226810 = 7E0C16
the Final answer: 01111110000011002 = 7E0C16