This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
5∙81+5∙80 = 5∙8+5∙1 = 40+5 = 4510
got It: 558 =4510
Translate the number 4510 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
45 | 16 | |
-32 | 2 | |
D | | |
|
the result of the conversion was:
4510 = 2D16
the Final answer: 558 = 2D16
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
558 = 5 5 = 5(=101) 5(=101) = 1011012
the Final answer: 558 = 1011012
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
001011012 = 0010 1101 = 0010(=2) 1101(=D) = 2D16
the Final answer: 001011018 = 2D16