This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
1F.4B716 = 1 F. 4 B 7 = 1(=0001) F(=1111). 4(=0100) B(=1011) 7(=0111) = 11111.0100101101112
answer: 1F.4B716 = 11111.0100101101112
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙161+15∙160+4∙16-1+11∙16-2+7∙16-3 = 1∙16+15∙1+4∙0.0625+11∙0.00390625+7∙0.000244140625 = 16+15+0.25+0.04296875+0.001708984375 = 31.29467773437510
got It: 1F.4B716 =31.29467773437510
Translate the number 31.29467773437510 в binary like this:
the Integer part of the number is divided by the base of the new number system:
31 | 2 | | | | |
-30 | 15 | 2 | | | |
1 | -14 | 7 | 2 | | |
| 1 | -6 | 3 | 2 | |
| | 1 | -2 | 1 | |
| | | 1 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 294677734375*2 |
0 | .58936*2 |
1 | .17871*2 |
0 | .35742*2 |
0 | .71484*2 |
1 | .42969*2 |
0 | .85938*2 |
1 | .71875*2 |
1 | .4375*2 |
0 | .875*2 |
1 | .75*2 |
the result of the conversion was:
31.29467773437510 = 11111.01001011012
answer: 1F.4B716 = 11111.01001011012