This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
14∙162+3∙161+4∙160+11∙16-1+12∙16-2 = 14∙256+3∙16+4∙1+11∙0.0625+12∙0.00390625 = 3584+48+4+0.6875+0.046875 = 3636.73437510
got It: E34.BC16 =3636.73437510
Translate the number 3636.73437510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
3636 | 8 | | | |
-3632 | 454 | 8 | | |
4 | -448 | 56 | 8 | |
| 6 | -56 | 7 | |
| | 0 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 734375*8 |
5 | .875*8 |
7 | .0*8 |
the result of the conversion was:
3636.73437510 = 7064.578
the Final answer: E34.BC16 = 7064.578
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
E34.BC16 = E 3 4. B C = E(=1110) 3(=0011) 4(=0100). B(=1011) C(=1100) = 111000110100.1011112
the Final answer: E34.BC16 = 111000110100.1011112
let\'s make a direct translation from binary to post-binary like this:
111000110100.1011112 = 111 000 110 100. 101 111 = 111(=7) 000(=0) 110(=6) 100(=4). 101(=5) 111(=7) = 7064.578
the Final answer: E34.BC16 = 7064.578