This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s make a direct translation from binary to post-binary like this:
1111101011012 = 111 110 101 101 = 111(=7) 110(=6) 101(=5) 101(=5) = 76558
answer: 1111101011012 = 76558
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙211+1∙210+1∙29+1∙28+1∙27+0∙26+1∙25+0∙24+1∙23+1∙22+0∙21+1∙20 = 1∙2048+1∙1024+1∙512+1∙256+1∙128+0∙64+1∙32+0∙16+1∙8+1∙4+0∙2+1∙1 = 2048+1024+512+256+128+0+32+0+8+4+0+1 = 401310
got It: 1111101011012 =401310
Translate the number 401310 в octal like this:
the Integer part of the number is divided by the base of the new number system:
4013 | 8 | | | |
-4008 | 501 | 8 | | |
5 | -496 | 62 | 8 | |
| 5 | -56 | 7 | |
| | 6 | | |
|
the result of the conversion was:
401310 = 76558
answer: 1111101011012 = 76558