This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
2∙82+3∙81+4∙80+5∙8-1+6∙8-2 = 2∙64+3∙8+4∙1+5∙0.125+6∙0.015625 = 128+24+4+0.625+0.09375 = 156.7187510
got It: 234.568 =156.7187510
Translate the number 156.7187510 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
156 | 16 | |
-144 | 9 | |
C | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 71875*16 |
B | .5*16 |
8 | .0*16 |
the result of the conversion was:
156.7187510 = 9C.B816
answer: 234.568 = 9C.B816
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
234.568 = 2 3 4. 5 6 = 2(=010) 3(=011) 4(=100). 5(=101) 6(=110) = 010011100.1011102
answer: 234.568 = 10011100.101112
Fill in the number with missing zeros on the right
let\'s do a direct translation from binary to hexadecimal like this:
10011100.101110002 = 1001 1100. 1011 1000 = 1001(=9) 1100(=C). 1011(=B) 1000(=8) = 9C.B816
answer: 10011100.101110008 = 9C.B816