This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
00011010101001012 = 0001 1010 1010 0101 = 0001(=1) 1010(=A) 1010(=A) 0101(=5) = 1AA516
answer: 00011010101001012 = 1AA516
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙215+0∙214+0∙213+1∙212+1∙211+0∙210+1∙29+0∙28+1∙27+0∙26+1∙25+0∙24+0∙23+1∙22+0∙21+1∙20 = 0∙32768+0∙16384+0∙8192+1∙4096+1∙2048+0∙1024+1∙512+0∙256+1∙128+0∙64+1∙32+0∙16+0∙8+1∙4+0∙2+1∙1 = 0+0+0+4096+2048+0+512+0+128+0+32+0+0+4+0+1 = 682110
got It: 00011010101001012 =682110
Translate the number 682110 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
6821 | 16 | | | |
-6816 | 426 | 16 | | |
5 | -416 | 26 | 16 | |
| A | -16 | 1 | |
| | A | | |
|
the result of the conversion was:
682110 = 1AA516
answer: 00011010101001012 = 1AA516