This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
4∙162+14∙161+7∙160+2∙16-1 = 4∙256+14∙16+7∙1+2∙0.0625 = 1024+224+7+0.125 = 1255.12510
got It: 4E7.216 =1255.12510
Translate the number 1255.12510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
1255 | 8 | | | |
-1248 | 156 | 8 | | |
7 | -152 | 19 | 8 | |
| 4 | -16 | 2 | |
| | 3 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 125*8 |
1 | .0*8 |
the result of the conversion was:
1255.12510 = 2347.18
answer: 4E7.216 = 2347.18
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
4E7.216 = 4 E 7. 2 = 4(=0100) E(=1110) 7(=0111). 2(=0010) = 10011100111.0012
answer: 4E7.216 = 10011100111.0012
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
010011100111.0012 = 010 011 100 111. 001 = 010(=2) 011(=3) 100(=4) 111(=7). 001(=1) = 2347.18
answer: 4E7.216 = 2347.18