This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
7∙82+5∙81+6∙80+6∙8-1+0∙8-2+3∙8-3 = 7∙64+5∙8+6∙1+6∙0.125+0∙0.015625+3∙0.001953125 = 448+40+6+0.75+0+0.005859375 = 494.75585937510
got It: 756.6038 =494.75585937510
Translate the number 494.75585937510 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
494 | 16 | | |
-480 | 30 | 16 | |
E | -16 | 1 | |
| E | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 755859375*16 |
C | .09375*16 |
1 | .5*16 |
8 | .0*16 |
the result of the conversion was:
494.75585937510 = 1EE.C1816
answer: 756.6038 = 1EE.C1816
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
756.6038 = 7 5 6. 6 0 3 = 7(=111) 5(=101) 6(=110). 6(=110) 0(=000) 3(=011) = 111101110.1100000112
answer: 756.6038 = 111101110.1100000112
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s do a direct translation from binary to hexadecimal like this:
000111101110.1100000110002 = 0001 1110 1110. 1100 0001 1000 = 0001(=1) 1110(=E) 1110(=E). 1100(=C) 0001(=1) 1000(=8) = 1EE.C1816
answer: 000111101110.1100000110008 = 1EE.C1816