This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
3447.2358 = 3 4 4 7. 2 3 5 = 3(=011) 4(=100) 4(=100) 7(=111). 2(=010) 3(=011) 5(=101) = 011100100111.0100111012
answer: 3447.2358 = 11100100111.0100111012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
3∙83+4∙82+4∙81+7∙80+2∙8-1+3∙8-2+5∙8-3 = 3∙512+4∙64+4∙8+7∙1+2∙0.125+3∙0.015625+5∙0.001953125 = 1536+256+32+7+0.25+0.046875+0.009765625 = 1831.30664062510
got It: 3447.2358 =1831.30664062510
Translate the number 1831.30664062510 в binary like this:
the Integer part of the number is divided by the base of the new number system:
1831 | 2 | | | | | | | | | | |
-1830 | 915 | 2 | | | | | | | | | |
1 | -914 | 457 | 2 | | | | | | | | |
| 1 | -456 | 228 | 2 | | | | | | | |
| | 1 | -228 | 114 | 2 | | | | | | |
| | | 0 | -114 | 57 | 2 | | | | | |
| | | | 0 | -56 | 28 | 2 | | | | |
| | | | | 1 | -28 | 14 | 2 | | | |
| | | | | | 0 | -14 | 7 | 2 | | |
| | | | | | | 0 | -6 | 3 | 2 | |
| | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | 1 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 306640625*2 |
0 | .61328*2 |
1 | .22656*2 |
0 | .45313*2 |
0 | .90625*2 |
1 | .8125*2 |
1 | .625*2 |
1 | .25*2 |
0 | .5*2 |
1 | .0*2 |
the result of the conversion was:
1831.30664062510 = 11100100111.0100111012
answer: 3447.2358 = 11100100111.0100111012