This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
88bae16 = 8 8 b a e = 8(=1000) 8(=1000) b(=1011) a(=1010) e(=1110) = 100010001011101011102
answer: 88bae16 = 100010001011101011102
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
8∙164+8∙163+11∙162+10∙161+14∙160 = 8∙65536+8∙4096+11∙256+10∙16+14∙1 = 524288+32768+2816+160+14 = 56004610
got It: 88bae16 =56004610
Translate the number 56004610 в binary like this:
the Integer part of the number is divided by the base of the new number system:
560046 | 2 | | | | | | | | | | | | | | | | | | | |
-560046 | 280023 | 2 | | | | | | | | | | | | | | | | | | |
0 | -280022 | 140011 | 2 | | | | | | | | | | | | | | | | | |
| 1 | -140010 | 70005 | 2 | | | | | | | | | | | | | | | | |
| | 1 | -70004 | 35002 | 2 | | | | | | | | | | | | | | | |
| | | 1 | -35002 | 17501 | 2 | | | | | | | | | | | | | | |
| | | | 0 | -17500 | 8750 | 2 | | | | | | | | | | | | | |
| | | | | 1 | -8750 | 4375 | 2 | | | | | | | | | | | | |
| | | | | | 0 | -4374 | 2187 | 2 | | | | | | | | | | | |
| | | | | | | 1 | -2186 | 1093 | 2 | | | | | | | | | | |
| | | | | | | | 1 | -1092 | 546 | 2 | | | | | | | | | |
| | | | | | | | | 1 | -546 | 273 | 2 | | | | | | | | |
| | | | | | | | | | 0 | -272 | 136 | 2 | | | | | | | |
| | | | | | | | | | | 1 | -136 | 68 | 2 | | | | | | |
| | | | | | | | | | | | 0 | -68 | 34 | 2 | | | | | |
| | | | | | | | | | | | | 0 | -34 | 17 | 2 | | | | |
| | | | | | | | | | | | | | 0 | -16 | 8 | 2 | | | |
| | | | | | | | | | | | | | | 1 | -8 | 4 | 2 | | |
| | | | | | | | | | | | | | | | 0 | -4 | 2 | 2 | |
| | | | | | | | | | | | | | | | | 0 | -2 | 1 | |
| | | | | | | | | | | | | | | | | | 0 | | |
|
the result of the conversion was:
56004610 = 100010001011101011102
answer: 88bae16 = 100010001011101011102