This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
9∙162+3∙161+13∙160 = 9∙256+3∙16+13∙1 = 2304+48+13 = 236510
got It: 93D16 =236510
Translate the number 236510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
2365 | 8 | | | |
-2360 | 295 | 8 | | |
5 | -288 | 36 | 8 | |
| 7 | -32 | 4 | |
| | 4 | | |
|
the result of the conversion was:
236510 = 44758
answer: 93D16 = 44758
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
93D16 = 9 3 D = 9(=1001) 3(=0011) D(=1101) = 1001001111012
answer: 93D16 = 1001001111012
let\'s make a direct translation from binary to post-binary like this:
1001001111012 = 100 100 111 101 = 100(=4) 100(=4) 111(=7) 101(=5) = 44758
answer: 93D16 = 44758