This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
2∙82+3∙81+2∙80+2∙8-1+3∙8-2 = 2∙64+3∙8+2∙1+2∙0.125+3∙0.015625 = 128+24+2+0.25+0.046875 = 154.29687510
got It: 232.238 =154.29687510
Translate the number 154.29687510 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
154 | 16 | |
-144 | 9 | |
A | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 296875*16 |
4 | .75*16 |
C | .0*16 |
the result of the conversion was:
154.29687510 = 9A.4C16
answer: 232.238 = 9A.4C16
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
232.238 = 2 3 2. 2 3 = 2(=010) 3(=011) 2(=010). 2(=010) 3(=011) = 010011010.0100112
answer: 232.238 = 10011010.0100112
Fill in the number with missing zeros on the right
let\'s do a direct translation from binary to hexadecimal like this:
10011010.010011002 = 1001 1010. 0100 1100 = 1001(=9) 1010(=A). 0100(=4) 1100(=C) = 9A.4C16
answer: 10011010.010011008 = 9A.4C16