This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
4∙82+1∙81+3∙80 = 4∙64+1∙8+3∙1 = 256+8+3 = 26710
got It: 4138 =26710
Translate the number 26710 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
267 | 16 | | |
-256 | 16 | 16 | |
B | -16 | 1 | |
| 0 | | |
|
the result of the conversion was:
26710 = 10B16
answer: 4138 = 10B16
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
4138 = 4 1 3 = 4(=100) 1(=001) 3(=011) = 1000010112
answer: 4138 = 1000010112
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
0001000010112 = 0001 0000 1011 = 0001(=1) 0000(=0) 1011(=B) = 10B16
answer: 0001000010118 = 10B16