This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
00111011.11012 = 0011 1011. 1101 = 0011(=3) 1011(=B). 1101(=D) = 3B.D16
answer: 00111011.11012 = 3B.D16
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙27+0∙26+1∙25+1∙24+1∙23+0∙22+1∙21+1∙20+1∙2-1+1∙2-2+0∙2-3+1∙2-4 = 0∙128+0∙64+1∙32+1∙16+1∙8+0∙4+1∙2+1∙1+1∙0.5+1∙0.25+0∙0.125+1∙0.0625 = 0+0+32+16+8+0+2+1+0.5+0.25+0+0.0625 = 59.812510
got It: 00111011.11012 =59.812510
Translate the number 59.812510 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
59 | 16 | |
-48 | 3 | |
B | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 8125*16 |
D | .0*16 |
the result of the conversion was:
59.812510 = 3B.D16
answer: 00111011.11012 = 3B.D16