This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
712616 = 7 1 2 6 = 7(=0111) 1(=0001) 2(=0010) 6(=0110) = 1110001001001102
answer: 712616 = 1110001001001102
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
7∙163+1∙162+2∙161+6∙160 = 7∙4096+1∙256+2∙16+6∙1 = 28672+256+32+6 = 2896610
got It: 712616 =2896610
Translate the number 2896610 в binary like this:
the Integer part of the number is divided by the base of the new number system:
28966 | 2 | | | | | | | | | | | | | | |
-28966 | 14483 | 2 | | | | | | | | | | | | | |
0 | -14482 | 7241 | 2 | | | | | | | | | | | | |
| 1 | -7240 | 3620 | 2 | | | | | | | | | | | |
| | 1 | -3620 | 1810 | 2 | | | | | | | | | | |
| | | 0 | -1810 | 905 | 2 | | | | | | | | | |
| | | | 0 | -904 | 452 | 2 | | | | | | | | |
| | | | | 1 | -452 | 226 | 2 | | | | | | | |
| | | | | | 0 | -226 | 113 | 2 | | | | | | |
| | | | | | | 0 | -112 | 56 | 2 | | | | | |
| | | | | | | | 1 | -56 | 28 | 2 | | | | |
| | | | | | | | | 0 | -28 | 14 | 2 | | | |
| | | | | | | | | | 0 | -14 | 7 | 2 | | |
| | | | | | | | | | | 0 | -6 | 3 | 2 | |
| | | | | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | | | | 1 | | |
|
the result of the conversion was:
2896610 = 1110001001001102
answer: 712616 = 1110001001001102