This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
13558 = 1 3 5 5 = 1(=001) 3(=011) 5(=101) 5(=101) = 0010111011012
answer: 13558 = 10111011012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙83+3∙82+5∙81+5∙80 = 1∙512+3∙64+5∙8+5∙1 = 512+192+40+5 = 74910
got It: 13558 =74910
Translate the number 74910 в binary like this:
the Integer part of the number is divided by the base of the new number system:
749 | 2 | | | | | | | | | |
-748 | 374 | 2 | | | | | | | | |
1 | -374 | 187 | 2 | | | | | | | |
| 0 | -186 | 93 | 2 | | | | | | |
| | 1 | -92 | 46 | 2 | | | | | |
| | | 1 | -46 | 23 | 2 | | | | |
| | | | 0 | -22 | 11 | 2 | | | |
| | | | | 1 | -10 | 5 | 2 | | |
| | | | | | 1 | -4 | 2 | 2 | |
| | | | | | | 1 | -2 | 1 | |
| | | | | | | | 0 | | |
|
the result of the conversion was:
74910 = 10111011012
answer: 13558 = 10111011012