This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
0∙811+1∙810+1∙89+1∙88+0∙87+1∙86+1∙85+1∙84+1∙83+1∙82+1∙81+0∙80 = 0∙8589934592+1∙1073741824+1∙134217728+1∙16777216+0∙2097152+1∙262144+1∙32768+1∙4096+1∙512+1∙64+1∙8+0∙1 = 0+1073741824+134217728+16777216+0+262144+32768+4096+512+64+8+0 = 122503636010
got It: 0111011111108 =122503636010
Translate the number 122503636010 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
1225036360 | 16 | | | | | | | |
-1225036352 | 76564772 | 16 | | | | | | |
8 | -76564768 | 4785298 | 16 | | | | | |
| 4 | -4785296 | 299081 | 16 | | | | |
| | 2 | -299072 | 18692 | 16 | | | |
| | | 9 | -18688 | 1168 | 16 | | |
| | | | 4 | -1168 | 73 | 16 | |
| | | | | 0 | -64 | 4 | |
| | | | | | 9 | | |
|
the result of the conversion was:
122503636010 = 4904924816
answer: 0111011111108 = 4904924816
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
0111011111108 = 0 1 1 1 0 1 1 1 1 1 1 0 = 0(=000) 1(=001) 1(=001) 1(=001) 0(=000) 1(=001) 1(=001) 1(=001) 1(=001) 1(=001) 1(=001) 0(=000) = 0000010010010000010010010010010010002
answer: 0111011111108 = 10010010000010010010010010010002
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
010010010000010010010010010010002 = 0100 1001 0000 0100 1001 0010 0100 1000 = 0100(=4) 1001(=9) 0000(=0) 0100(=4) 1001(=9) 0010(=2) 0100(=4) 1000(=8) = 4904924816
answer: 010010010000010010010010010010008 = 4904924816