This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the right
let\'s do a direct translation from binary to hexadecimal like this:
11011101.110111002 = 1101 1101. 1101 1100 = 1101(=D) 1101(=D). 1101(=D) 1100(=C) = DD.DC16
answer: 11011101.110111002 = DD.DC16
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙27+1∙26+0∙25+1∙24+1∙23+1∙22+0∙21+1∙20+1∙2-1+1∙2-2+0∙2-3+1∙2-4+1∙2-5+1∙2-6+0∙2-7+0∙2-8 = 1∙128+1∙64+0∙32+1∙16+1∙8+1∙4+0∙2+1∙1+1∙0.5+1∙0.25+0∙0.125+1∙0.0625+1∙0.03125+1∙0.015625+0∙0.0078125+0∙0.00390625 = 128+64+0+16+8+4+0+1+0.5+0.25+0+0.0625+0.03125+0.015625+0+0 = 221.85937510
got It: 11011101.110111002 =221.85937510
Translate the number 221.85937510 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
221 | 16 | |
-208 | D | |
D | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 859375*16 |
D | .75*16 |
C | .0*16 |
the result of the conversion was:
221.85937510 = DD.DC16
answer: 11011101.110111002 = DD.DC16