This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
3∙83+5∙82+7∙81+6∙80 = 3∙512+5∙64+7∙8+6∙1 = 1536+320+56+6 = 191810
got It: 35768 =191810
Translate the number 191810 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
1918 | 16 | | |
-1904 | 119 | 16 | |
E | -112 | 7 | |
| 7 | | |
|
the result of the conversion was:
191810 = 77E16
the Final answer: 35768 = 77E16
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
35768 = 3 5 7 6 = 3(=011) 5(=101) 7(=111) 6(=110) = 0111011111102
the Final answer: 35768 = 111011111102
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
0111011111102 = 0111 0111 1110 = 0111(=7) 0111(=7) 1110(=E) = 77E16
the Final answer: 0111011111108 = 77E16