This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
2∙82+6∙81+1∙80 = 2∙64+6∙8+1∙1 = 128+48+1 = 17710
got It: 2618 =17710
Translate the number 17710 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
177 | 16 | |
-176 | B | |
1 | | |
|
the result of the conversion was:
17710 = B116
the Final answer: 2618 = B116
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
2618 = 2 6 1 = 2(=010) 6(=110) 1(=001) = 0101100012
the Final answer: 2618 = 101100012
let\'s do a direct translation from binary to hexadecimal like this:
101100012 = 1011 0001 = 1011(=B) 0001(=1) = B116
the Final answer: 101100018 = B116