This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
456548 = 4 5 6 5 4 = 4(=100) 5(=101) 6(=110) 5(=101) 4(=100) = 1001011101011002
answer: 456548 = 1001011101011002
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
4∙84+5∙83+6∙82+5∙81+4∙80 = 4∙4096+5∙512+6∙64+5∙8+4∙1 = 16384+2560+384+40+4 = 1937210
got It: 456548 =1937210
Translate the number 1937210 в binary like this:
the Integer part of the number is divided by the base of the new number system:
19372 | 2 | | | | | | | | | | | | | | |
-19372 | 9686 | 2 | | | | | | | | | | | | | |
0 | -9686 | 4843 | 2 | | | | | | | | | | | | |
| 0 | -4842 | 2421 | 2 | | | | | | | | | | | |
| | 1 | -2420 | 1210 | 2 | | | | | | | | | | |
| | | 1 | -1210 | 605 | 2 | | | | | | | | | |
| | | | 0 | -604 | 302 | 2 | | | | | | | | |
| | | | | 1 | -302 | 151 | 2 | | | | | | | |
| | | | | | 0 | -150 | 75 | 2 | | | | | | |
| | | | | | | 1 | -74 | 37 | 2 | | | | | |
| | | | | | | | 1 | -36 | 18 | 2 | | | | |
| | | | | | | | | 1 | -18 | 9 | 2 | | | |
| | | | | | | | | | 0 | -8 | 4 | 2 | | |
| | | | | | | | | | | 1 | -4 | 2 | 2 | |
| | | | | | | | | | | | 0 | -2 | 1 | |
| | | | | | | | | | | | | 0 | | |
|
the result of the conversion was:
1937210 = 1001011101011002
answer: 456548 = 1001011101011002