This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
575616 = 5 7 5 6 = 5(=0101) 7(=0111) 5(=0101) 6(=0110) = 1010111010101102
answer: 575616 = 1010111010101102
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
5∙163+7∙162+5∙161+6∙160 = 5∙4096+7∙256+5∙16+6∙1 = 20480+1792+80+6 = 2235810
got It: 575616 =2235810
Translate the number 2235810 в binary like this:
the Integer part of the number is divided by the base of the new number system:
22358 | 2 | | | | | | | | | | | | | | |
-22358 | 11179 | 2 | | | | | | | | | | | | | |
0 | -11178 | 5589 | 2 | | | | | | | | | | | | |
| 1 | -5588 | 2794 | 2 | | | | | | | | | | | |
| | 1 | -2794 | 1397 | 2 | | | | | | | | | | |
| | | 0 | -1396 | 698 | 2 | | | | | | | | | |
| | | | 1 | -698 | 349 | 2 | | | | | | | | |
| | | | | 0 | -348 | 174 | 2 | | | | | | | |
| | | | | | 1 | -174 | 87 | 2 | | | | | | |
| | | | | | | 0 | -86 | 43 | 2 | | | | | |
| | | | | | | | 1 | -42 | 21 | 2 | | | | |
| | | | | | | | | 1 | -20 | 10 | 2 | | | |
| | | | | | | | | | 1 | -10 | 5 | 2 | | |
| | | | | | | | | | | 0 | -4 | 2 | 2 | |
| | | | | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | | | | 0 | | |
|
the result of the conversion was:
2235810 = 1010111010101102
answer: 575616 = 1010111010101102