This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
CF916 = C F 9 = C(=1100) F(=1111) 9(=1001) = 1100111110012
answer: CF916 = 1100111110012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
12∙162+15∙161+9∙160 = 12∙256+15∙16+9∙1 = 3072+240+9 = 332110
got It: CF916 =332110
Translate the number 332110 в binary like this:
the Integer part of the number is divided by the base of the new number system:
3321 | 2 | | | | | | | | | | | |
-3320 | 1660 | 2 | | | | | | | | | | |
1 | -1660 | 830 | 2 | | | | | | | | | |
| 0 | -830 | 415 | 2 | | | | | | | | |
| | 0 | -414 | 207 | 2 | | | | | | | |
| | | 1 | -206 | 103 | 2 | | | | | | |
| | | | 1 | -102 | 51 | 2 | | | | | |
| | | | | 1 | -50 | 25 | 2 | | | | |
| | | | | | 1 | -24 | 12 | 2 | | | |
| | | | | | | 1 | -12 | 6 | 2 | | |
| | | | | | | | 0 | -6 | 3 | 2 | |
| | | | | | | | | 0 | -2 | 1 | |
| | | | | | | | | | 1 | | |
|
the result of the conversion was:
332110 = 1100111110012
answer: CF916 = 1100111110012