This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0001101010012 = 000 110 101 001 = 000(=0) 110(=6) 101(=5) 001(=1) = 06518
the Final answer: 001101010012 = 06518
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙211+0∙210+0∙29+1∙28+1∙27+0∙26+1∙25+0∙24+1∙23+0∙22+0∙21+1∙20 = 0∙2048+0∙1024+0∙512+1∙256+1∙128+0∙64+1∙32+0∙16+1∙8+0∙4+0∙2+1∙1 = 0+0+0+256+128+0+32+0+8+0+0+1 = 42510
got It: 0001101010012 =42510
Translate the number 42510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
425 | 8 | | |
-424 | 53 | 8 | |
1 | -48 | 6 | |
| 5 | | |
|
the result of the conversion was:
42510 = 6518
the Final answer: 001101010012 = 6518