This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
010011101.1102 = 010 011 101. 110 = 010(=2) 011(=3) 101(=5). 110(=6) = 235.68
answer: 10011101.112 = 235.68
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙28+1∙27+0∙26+0∙25+1∙24+1∙23+1∙22+0∙21+1∙20+1∙2-1+1∙2-2+0∙2-3 = 0∙256+1∙128+0∙64+0∙32+1∙16+1∙8+1∙4+0∙2+1∙1+1∙0.5+1∙0.25+0∙0.125 = 0+128+0+0+16+8+4+0+1+0.5+0.25+0 = 157.7510
got It: 010011101.1102 =157.7510
Translate the number 157.7510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
157 | 8 | | |
-152 | 19 | 8 | |
5 | -16 | 2 | |
| 3 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 75*8 |
6 | .0*8 |
the result of the conversion was:
157.7510 = 235.68
answer: 10011101.112 = 235.68