This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
011101012 = 0111 0101 = 0111(=7) 0101(=5) = 7516
the Final answer: 011101012 = 7516
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙27+1∙26+1∙25+1∙24+0∙23+1∙22+0∙21+1∙20 = 0∙128+1∙64+1∙32+1∙16+0∙8+1∙4+0∙2+1∙1 = 0+64+32+16+0+4+0+1 = 11710
got It: 011101012 =11710
Translate the number 11710 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
117 | 16 | |
-112 | 7 | |
5 | | |
|
the result of the conversion was:
11710 = 7516
the Final answer: 011101012 = 7516