This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0011010112 = 001 101 011 = 001(=1) 101(=5) 011(=3) = 1538
the Final answer: 11010112 = 1538
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙28+0∙27+1∙26+1∙25+0∙24+1∙23+0∙22+1∙21+1∙20 = 0∙256+0∙128+1∙64+1∙32+0∙16+1∙8+0∙4+1∙2+1∙1 = 0+0+64+32+0+8+0+2+1 = 10710
got It: 0011010112 =10710
Translate the number 10710 в octal like this:
the Integer part of the number is divided by the base of the new number system:
107 | 8 | | |
-104 | 13 | 8 | |
3 | -8 | 1 | |
| 5 | | |
|
the result of the conversion was:
10710 = 1538
the Final answer: 11010112 = 1538