This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0110102 = 011 010 = 011(=3) 010(=2) = 328
the Final answer: 110102 = 328
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙25+1∙24+1∙23+0∙22+1∙21+0∙20 = 0∙32+1∙16+1∙8+0∙4+1∙2+0∙1 = 0+16+8+0+2+0 = 2610
got It: 0110102 =2610
Translate the number 2610 в octal like this:
the Integer part of the number is divided by the base of the new number system:
26 | 8 | |
-24 | 3 | |
2 | | |
|
the result of the conversion was:
2610 = 328
the Final answer: 110102 = 328