This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s make a direct translation from binary to post-binary like this:
111110001.1001102 = 111 110 001. 100 110 = 111(=7) 110(=6) 001(=1). 100(=4) 110(=6) = 761.468
answer: 111110001.1001102 = 761.468
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙28+1∙27+1∙26+1∙25+1∙24+0∙23+0∙22+0∙21+1∙20+1∙2-1+0∙2-2+0∙2-3+1∙2-4+1∙2-5+0∙2-6 = 1∙256+1∙128+1∙64+1∙32+1∙16+0∙8+0∙4+0∙2+1∙1+1∙0.5+0∙0.25+0∙0.125+1∙0.0625+1∙0.03125+0∙0.015625 = 256+128+64+32+16+0+0+0+1+0.5+0+0+0.0625+0.03125+0 = 497.5937510
got It: 111110001.1001102 =497.5937510
Translate the number 497.5937510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
497 | 8 | | |
-496 | 62 | 8 | |
1 | -56 | 7 | |
| 6 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 59375*8 |
4 | .75*8 |
6 | .0*8 |
the result of the conversion was:
497.5937510 = 761.468
answer: 111110001.1001102 = 761.468