This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
15∙163+2∙162+9∙161+7∙160 = 15∙4096+2∙256+9∙16+7∙1 = 61440+512+144+7 = 6210310
got It: F29716 =6210310
Translate the number 6210310 в octal like this:
the Integer part of the number is divided by the base of the new number system:
62103 | 8 | | | | | |
-62096 | 7762 | 8 | | | | |
7 | -7760 | 970 | 8 | | | |
| 2 | -968 | 121 | 8 | | |
| | 2 | -120 | 15 | 8 | |
| | | 1 | -8 | 1 | |
| | | | 7 | | |
|
the result of the conversion was:
6210310 = 1712278
answer: F29716 = 1712278
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
F29716 = F 2 9 7 = F(=1111) 2(=0010) 9(=1001) 7(=0111) = 11110010100101112
answer: F29716 = 11110010100101112
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0011110010100101112 = 001 111 001 010 010 111 = 001(=1) 111(=7) 001(=1) 010(=2) 010(=2) 111(=7) = 1712278
answer: F29716 = 1712278