This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
1∙163+13∙162+7∙161+15∙160 = 1∙4096+13∙256+7∙16+15∙1 = 4096+3328+112+15 = 755110
got It: 1D7F16 =755110
Translate the number 755110 в octal like this:
the Integer part of the number is divided by the base of the new number system:
7551 | 8 | | | | |
-7544 | 943 | 8 | | | |
7 | -936 | 117 | 8 | | |
| 7 | -112 | 14 | 8 | |
| | 5 | -8 | 1 | |
| | | 6 | | |
|
the result of the conversion was:
755110 = 165778
answer: 1D7F16 = 165778
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
1D7F16 = 1 D 7 F = 1(=0001) D(=1101) 7(=0111) F(=1111) = 11101011111112
answer: 1D7F16 = 11101011111112
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0011101011111112 = 001 110 101 111 111 = 001(=1) 110(=6) 101(=5) 111(=7) 111(=7) = 165778
answer: 1D7F16 = 165778