This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
100.1102 = 100. 110 = 100(=4). 110(=6) = 4.68
answer: 100.112 = 4.68
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙22+0∙21+0∙20+1∙2-1+1∙2-2+0∙2-3 = 1∙4+0∙2+0∙1+1∙0.5+1∙0.25+0∙0.125 = 4+0+0+0.5+0.25+0 = 4.7510
got It: 100.1102 =4.7510
Translate the number 4.7510 в octal like this:
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 75*8 |
6 | .0*8 |
the result of the conversion was:
4.7510 = 4.68
answer: 100.112 = 4.68