This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
7∙81+5∙80+6∙8-1+7∙8-2 = 7∙8+5∙1+6∙0.125+7∙0.015625 = 56+5+0.75+0.109375 = 61.85937510
got It: 75.678 =61.85937510
Translate the number 61.85937510 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
61 | 16 | |
-48 | 3 | |
D | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 859375*16 |
D | .75*16 |
C | .0*16 |
the result of the conversion was:
61.85937510 = 3D.DC16
the Final answer: 75.678 = 3D.DC16
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
75.678 = 7 5. 6 7 = 7(=111) 5(=101). 6(=110) 7(=111) = 111101.1101112
the Final answer: 75.678 = 111101.1101112
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s do a direct translation from binary to hexadecimal like this:
00111101.110111002 = 0011 1101. 1101 1100 = 0011(=3) 1101(=D). 1101(=D) 1100(=C) = 3D.DC16
the Final answer: 00111101.110111008 = 3D.DC16