This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
666616 = 6 6 6 6 = 6(=0110) 6(=0110) 6(=0110) 6(=0110) = 1100110011001102
answer: 666616 = 1100110011001102
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
6∙163+6∙162+6∙161+6∙160 = 6∙4096+6∙256+6∙16+6∙1 = 24576+1536+96+6 = 2621410
got It: 666616 =2621410
Translate the number 2621410 в binary like this:
the Integer part of the number is divided by the base of the new number system:
26214 | 2 | | | | | | | | | | | | | | |
-26214 | 13107 | 2 | | | | | | | | | | | | | |
0 | -13106 | 6553 | 2 | | | | | | | | | | | | |
| 1 | -6552 | 3276 | 2 | | | | | | | | | | | |
| | 1 | -3276 | 1638 | 2 | | | | | | | | | | |
| | | 0 | -1638 | 819 | 2 | | | | | | | | | |
| | | | 0 | -818 | 409 | 2 | | | | | | | | |
| | | | | 1 | -408 | 204 | 2 | | | | | | | |
| | | | | | 1 | -204 | 102 | 2 | | | | | | |
| | | | | | | 0 | -102 | 51 | 2 | | | | | |
| | | | | | | | 0 | -50 | 25 | 2 | | | | |
| | | | | | | | | 1 | -24 | 12 | 2 | | | |
| | | | | | | | | | 1 | -12 | 6 | 2 | | |
| | | | | | | | | | | 0 | -6 | 3 | 2 | |
| | | | | | | | | | | | 0 | -2 | 1 | |
| | | | | | | | | | | | | 1 | | |
|
the result of the conversion was:
2621410 = 1100110011001102
answer: 666616 = 1100110011001102