This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
56.358 = 5 6. 3 5 = 5(=101) 6(=110). 3(=011) 5(=101) = 101110.0111012
answer: 56.358 = 101110.0111012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
5∙81+6∙80+3∙8-1+5∙8-2 = 5∙8+6∙1+3∙0.125+5∙0.015625 = 40+6+0.375+0.078125 = 46.45312510
got It: 56.358 =46.45312510
Translate the number 46.45312510 в binary like this:
the Integer part of the number is divided by the base of the new number system:
46 | 2 | | | | | |
-46 | 23 | 2 | | | | |
0 | -22 | 11 | 2 | | | |
| 1 | -10 | 5 | 2 | | |
| | 1 | -4 | 2 | 2 | |
| | | 1 | -2 | 1 | |
| | | | 0 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 453125*2 |
0 | .90625*2 |
1 | .8125*2 |
1 | .625*2 |
1 | .25*2 |
0 | .5*2 |
1 | .0*2 |
the result of the conversion was:
46.45312510 = 101110.0111012
answer: 56.358 = 101110.0111012