This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
011111.0001.10011001101002 = 011 111. 000 1.1 001 100 110 100 = 011(=3) 111(=7). 000(=0) 1.1(=3) 001(=1) 100(=4) 110(=6) 100(=4) = 37.0314648
answer: 11111.0001.100110011012 = 37.0314648
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙25+1∙24+1∙23+1∙22+1∙21+1∙20+0∙2-1+0∙2-2+0∙2-3+1∙2-4+.∙2-5+1∙2-6+0∙2-7+0∙2-8+1∙2-9+1∙2-10+0∙2-11+0∙2-12+1∙2-13+1∙2-14+0∙2-15+1∙2-16+0∙2-17+0∙2-18 = 0∙32+1∙16+1∙8+1∙4+1∙2+1∙1+0∙0.5+0∙0.25+0∙0.125+1∙0.0625+.∙0.03125+1∙0.015625+0∙0.0078125+0∙0.00390625+1∙0.001953125+1∙0.0009765625+0∙0.00048828125+0∙0.000244140625+1∙0.0001220703125+1∙6.103515625E-5+0∙3.0517578125E-5+1∙1.52587890625E-5+0∙7.62939453125E-6+0∙3.814697265625E-6 = 0+16+8+4+2+1+0+0+0+0.0625+0+0.015625+0+0+0.001953125+0.0009765625+0+0+0.0001220703125+6.103515625E-5+0+1.52587890625E-5+0+0 = 31.08125305175781210
got It: 011111.0001.10011001101002 =31.08125305175781210
Translate the number 31.08125305175781210 в octal like this:
the Integer part of the number is divided by the base of the new number system:
31 | 8 | |
-24 | 3 | |
7 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 081253051757812*8 |
0 | .65002*8 |
5 | .2002*8 |
1 | .60156*8 |
4 | .8125*8 |
6 | .5*8 |
3 | .0*8 |
7 | .0*8 |
7 | .0*8 |
7 | .0*8 |
7 | .0*8 |
the result of the conversion was:
31.08125305175781210 = 37.05146377778
answer: 11111.0001.100110011012 = 37.05146377778