This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
01101011.01012 = 0110 1011. 0101 = 0110(=6) 1011(=B). 0101(=5) = 6B.516
answer: 01101011.01012 = 6B.516
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙27+1∙26+1∙25+0∙24+1∙23+0∙22+1∙21+1∙20+0∙2-1+1∙2-2+0∙2-3+1∙2-4 = 0∙128+1∙64+1∙32+0∙16+1∙8+0∙4+1∙2+1∙1+0∙0.5+1∙0.25+0∙0.125+1∙0.0625 = 0+64+32+0+8+0+2+1+0+0.25+0+0.0625 = 107.312510
got It: 01101011.01012 =107.312510
Translate the number 107.312510 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
107 | 16 | |
-96 | 6 | |
B | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 3125*16 |
5 | .0*16 |
the result of the conversion was:
107.312510 = 6B.516
answer: 01101011.01012 = 6B.516