This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
5∙82+7∙81+6∙80 = 5∙64+7∙8+6∙1 = 320+56+6 = 38210
got It: 5768 =38210
Translate the number 38210 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
382 | 16 | | |
-368 | 23 | 16 | |
E | -16 | 1 | |
| 7 | | |
|
the result of the conversion was:
38210 = 17E16
the Final answer: 5768 = 17E16
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
5768 = 5 7 6 = 5(=101) 7(=111) 6(=110) = 1011111102
the Final answer: 5768 = 1011111102
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
0001011111102 = 0001 0111 1110 = 0001(=1) 0111(=7) 1110(=E) = 17E16
the Final answer: 0001011111108 = 17E16