This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
1∙82+4∙81+7∙80+6∙8-1+7∙8-2 = 1∙64+4∙8+7∙1+6∙0.125+7∙0.015625 = 64+32+7+0.75+0.109375 = 103.85937510
got It: 147.678 =103.85937510
Translate the number 103.85937510 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
103 | 16 | |
-96 | 6 | |
7 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 859375*16 |
D | .75*16 |
C | .0*16 |
the result of the conversion was:
103.85937510 = 67.DC16
the Final answer: 147.678 = 67.DC16
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
147.678 = 1 4 7. 6 7 = 1(=001) 4(=100) 7(=111). 6(=110) 7(=111) = 001100111.1101112
the Final answer: 147.678 = 1100111.1101112
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s do a direct translation from binary to hexadecimal like this:
01100111.110111002 = 0110 0111. 1101 1100 = 0110(=6) 0111(=7). 1101(=D) 1100(=C) = 67.DC16
the Final answer: 01100111.110111008 = 67.DC16