This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
00111010001011112 = 0011 1010 0010 1111 = 0011(=3) 1010(=A) 0010(=2) 1111(=F) = 3A2F16
the Final answer: 00111010001011112 = 3A2F16
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙215+0∙214+1∙213+1∙212+1∙211+0∙210+1∙29+0∙28+0∙27+0∙26+1∙25+0∙24+1∙23+1∙22+1∙21+1∙20 = 0∙32768+0∙16384+1∙8192+1∙4096+1∙2048+0∙1024+1∙512+0∙256+0∙128+0∙64+1∙32+0∙16+1∙8+1∙4+1∙2+1∙1 = 0+0+8192+4096+2048+0+512+0+0+0+32+0+8+4+2+1 = 1489510
got It: 00111010001011112 =1489510
Translate the number 1489510 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
14895 | 16 | | | |
-14880 | 930 | 16 | | |
F | -928 | 58 | 16 | |
| 2 | -48 | 3 | |
| | A | | |
|
the result of the conversion was:
1489510 = 3A2F16
the Final answer: 00111010001011112 = 3A2F16