This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
ffe016 = f f e 0 = f(=1111) f(=1111) e(=1110) 0(=0000) = 11111111111000002
answer: ffe016 = 11111111111000002
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
15∙163+15∙162+14∙161+0∙160 = 15∙4096+15∙256+14∙16+0∙1 = 61440+3840+224+0 = 6550410
got It: ffe016 =6550410
Translate the number 6550410 в binary like this:
the Integer part of the number is divided by the base of the new number system:
65504 | 2 | | | | | | | | | | | | | | | |
-65504 | 32752 | 2 | | | | | | | | | | | | | | |
0 | -32752 | 16376 | 2 | | | | | | | | | | | | | |
| 0 | -16376 | 8188 | 2 | | | | | | | | | | | | |
| | 0 | -8188 | 4094 | 2 | | | | | | | | | | | |
| | | 0 | -4094 | 2047 | 2 | | | | | | | | | | |
| | | | 0 | -2046 | 1023 | 2 | | | | | | | | | |
| | | | | 1 | -1022 | 511 | 2 | | | | | | | | |
| | | | | | 1 | -510 | 255 | 2 | | | | | | | |
| | | | | | | 1 | -254 | 127 | 2 | | | | | | |
| | | | | | | | 1 | -126 | 63 | 2 | | | | | |
| | | | | | | | | 1 | -62 | 31 | 2 | | | | |
| | | | | | | | | | 1 | -30 | 15 | 2 | | | |
| | | | | | | | | | | 1 | -14 | 7 | 2 | | |
| | | | | | | | | | | | 1 | -6 | 3 | 2 | |
| | | | | | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | | | | | 1 | | |
|
the result of the conversion was:
6550410 = 11111111111000002
answer: ffe016 = 11111111111000002