This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
001100011.1011102 = 001 100 011. 101 110 = 001(=1) 100(=4) 011(=3). 101(=5) 110(=6) = 143.568
answer: 1100011.101112 = 143.568
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙28+0∙27+1∙26+1∙25+0∙24+0∙23+0∙22+1∙21+1∙20+1∙2-1+0∙2-2+1∙2-3+1∙2-4+1∙2-5+0∙2-6 = 0∙256+0∙128+1∙64+1∙32+0∙16+0∙8+0∙4+1∙2+1∙1+1∙0.5+0∙0.25+1∙0.125+1∙0.0625+1∙0.03125+0∙0.015625 = 0+0+64+32+0+0+0+2+1+0.5+0+0.125+0.0625+0.03125+0 = 99.7187510
got It: 001100011.1011102 =99.7187510
Translate the number 99.7187510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
99 | 8 | | |
-96 | 12 | 8 | |
3 | -8 | 1 | |
| 4 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 71875*8 |
5 | .75*8 |
6 | .0*8 |
the result of the conversion was:
99.7187510 = 143.568
answer: 1100011.101112 = 143.568