This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s make a direct translation from binary to post-binary like this:
110111.0101012 = 110 111. 010 101 = 110(=6) 111(=7). 010(=2) 101(=5) = 67.258
answer: 110111.0101012 = 67.258
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙25+1∙24+0∙23+1∙22+1∙21+1∙20+0∙2-1+1∙2-2+0∙2-3+1∙2-4+0∙2-5+1∙2-6 = 1∙32+1∙16+0∙8+1∙4+1∙2+1∙1+0∙0.5+1∙0.25+0∙0.125+1∙0.0625+0∙0.03125+1∙0.015625 = 32+16+0+4+2+1+0+0.25+0+0.0625+0+0.015625 = 55.32812510
got It: 110111.0101012 =55.32812510
Translate the number 55.32812510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
55 | 8 | |
-48 | 6 | |
7 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 328125*8 |
2 | .625*8 |
5 | .0*8 |
the result of the conversion was:
55.32812510 = 67.258
answer: 110111.0101012 = 67.258