This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
2∙162+6∙161+8∙160 = 2∙256+6∙16+8∙1 = 512+96+8 = 61610
got It: 26816 =61610
Translate the number 61610 в octal like this:
the Integer part of the number is divided by the base of the new number system:
616 | 8 | | | |
-616 | 77 | 8 | | |
0 | -72 | 9 | 8 | |
| 5 | -8 | 1 | |
| | 1 | | |
|
the result of the conversion was:
61610 = 11508
answer: 26816 = 11508
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
26816 = 2 6 8 = 2(=0010) 6(=0110) 8(=1000) = 10011010002
answer: 26816 = 10011010002
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0010011010002 = 001 001 101 000 = 001(=1) 001(=1) 101(=5) 000(=0) = 11508
answer: 26816 = 11508