This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
10∙163+3∙162+13∙161+12∙160+1∙16-1+2∙16-2 = 10∙4096+3∙256+13∙16+12∙1+1∙0.0625+2∙0.00390625 = 40960+768+208+12+0.0625+0.0078125 = 41948.070312510
got It: A3DC.1216 =41948.070312510
Translate the number 41948.070312510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
41948 | 8 | | | | | |
-41944 | 5243 | 8 | | | | |
4 | -5240 | 655 | 8 | | | |
| 3 | -648 | 81 | 8 | | |
| | 7 | -80 | 10 | 8 | |
| | | 1 | -8 | 1 | |
| | | | 2 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 0703125*8 |
0 | .5625*8 |
4 | .5*8 |
4 | .0*8 |
the result of the conversion was:
41948.070312510 = 121734.0448
answer: A3DC.1216 = 121734.0448
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
A3DC.1216 = A 3 D C. 1 2 = A(=1010) 3(=0011) D(=1101) C(=1100). 1(=0001) 2(=0010) = 1010001111011100.00010012
answer: A3DC.1216 = 1010001111011100.00010012
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
001010001111011100.0001001002 = 001 010 001 111 011 100. 000 100 100 = 001(=1) 010(=2) 001(=1) 111(=7) 011(=3) 100(=4). 000(=0) 100(=4) 100(=4) = 121734.0448
answer: A3DC.1216 = 121734.0448