This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
000110011.1011002 = 000 110 011. 101 100 = 000(=0) 110(=6) 011(=3). 101(=5) 100(=4) = 063.548
the Final answer: 0110011.10112 = 063.548
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙28+0∙27+0∙26+1∙25+1∙24+0∙23+0∙22+1∙21+1∙20+1∙2-1+0∙2-2+1∙2-3+1∙2-4+0∙2-5+0∙2-6 = 0∙256+0∙128+0∙64+1∙32+1∙16+0∙8+0∙4+1∙2+1∙1+1∙0.5+0∙0.25+1∙0.125+1∙0.0625+0∙0.03125+0∙0.015625 = 0+0+0+32+16+0+0+2+1+0.5+0+0.125+0.0625+0+0 = 51.687510
got It: 000110011.1011002 =51.687510
Translate the number 51.687510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
51 | 8 | |
-48 | 6 | |
3 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 6875*8 |
5 | .5*8 |
4 | .0*8 |
the result of the conversion was:
51.687510 = 63.548
the Final answer: 0110011.10112 = 63.548