This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
4∙82+5∙81+2∙80 = 4∙64+5∙8+2∙1 = 256+40+2 = 29810
got It: 4528 =29810
Translate the number 29810 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
298 | 16 | | |
-288 | 18 | 16 | |
A | -16 | 1 | |
| 2 | | |
|
the result of the conversion was:
29810 = 12A16
answer: 4528 = 12A16
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
4528 = 4 5 2 = 4(=100) 5(=101) 2(=010) = 1001010102
answer: 4528 = 1001010102
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
0001001010102 = 0001 0010 1010 = 0001(=1) 0010(=2) 1010(=A) = 12A16
answer: 0001001010108 = 12A16