This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
000.1101102 = 000. 110 110 = 000(=0). 110(=6) 110(=6) = 0.668
the Final answer: 0.110112 = 0.668
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙22+0∙21+0∙20+1∙2-1+1∙2-2+0∙2-3+1∙2-4+1∙2-5+0∙2-6 = 0∙4+0∙2+0∙1+1∙0.5+1∙0.25+0∙0.125+1∙0.0625+1∙0.03125+0∙0.015625 = 0+0+0+0.5+0.25+0+0.0625+0.03125+0 = 0.8437510
got It: 000.1101102 =0.8437510
Translate the number 0.8437510 в octal like this:
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 84375*8 |
6 | .75*8 |
6 | .0*8 |
the result of the conversion was:
0.8437510 = 0.668
the Final answer: 0.110112 = 0.668